The domain of f-x- - -2-2-x-2-2x- is-1- 0- 1-2- - 0-3- -0- 1-4- R-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Area between x=g(y) and y Axis

The domain of...

Question

The domain of f(x) = \sqrt{2-2^x-2^{2x}} is(1) \lbrack0, 1\rbrack(2) (, 0\rbrack(3) (0, 1)(4) R^{

Open in App

Solution

Suggest Corrections

Similar questions

f (x) = {log}_{1 / 2} (x - \frac{1}{2}) + {log}_{2} \sqrt{4 x^{2} - 4 x + 5}

$2^{(2 x + 2)} - 14 \times 2^{(x + 1)} + 4 = 0$ , then which of the following is true?

f (x) = \sqrt{{({log}_{5} 2)}^{2 x + 5} - {({log}_{4} 25)}^{x - 7}}

Given that $g (x) = [f (x) - 1]^{2}$ . Find the domain of f(x) = 1 - 2x, given that $0 \leq g (x) < 4$ .

f (x) = \sqrt{\frac{2^{x} + 3^{x}}{2^{x} - 3^{x}}}

Join BYJU'S Learning Program