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Byju's Answer
Standard XII
Mathematics
Monotonically Increasing Functions
The domain of...
Question
The domain of
f
(
x
)
=
√
cos
(
sin
x
)
+
√
log
x
{
x
}
(where
{
.
}
is fractional part of
x
) is
A
[
1
,
π
)
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B
(
0
,
2
π
)
−
[
1
,
π
)
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C
(
0
,
π
2
)
−
{
1
}
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D
(
0
,
1
)
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Solution
The correct option is
D
(
0
,
1
)
f
(
x
)
=
√
c
o
s
(
s
i
n
x
)
+
√
l
o
g
x
{
x
}
−
1
⩽
s
i
n
x
⩽
1
∀
x
ϵ
R
⇒
0
<
c
o
s
(
s
i
n
x
)
⩽
1
∀
x
ϵ
R
For function to be real
l
o
g
x
{
x
}
>
0
and
{
x
}
≠
0
and
x
>
0
⇒
x
ϵ
(
0
,
1
)
∴
Range of f is (0,1)
Suggest Corrections
0
Similar questions
Q.
Domain of
f
(
x
)
=
√
cos
(
sin
x
)
+
√
log
x
{
x
}
; where {.} denotes the fractional part is
Q.
If
f
(
x
)
=
⎧
⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪
⎩
sin
{
cos
x
}
x
−
π
2
,
x
≠
π
2
1
,
x
=
π
2
, where {.} represents the fractional part function,
then
lim
x
→
π
/
2
f
(
x
)
is?
Q.
Let
f
(
x
)
=
cos
−
1
(
1
−
{
x
}
2
)
sin
−
1
(
1
−
{
x
}
)
{
x
}
−
{
x
}
3
,
x
≠
0
, where
{
x
}
denotes fractional part of
x
. Then
(correct answer + 1, wrong answer - 0.25)
Q.
If
∫
√
1
−
x
1
+
x
d
x
=
√
1
−
x
2
+
f
(
x
)
+
c
,
x
∈
[
0
,
1
)
where
f
(
0
)
=
−
π
2
then
f
(
1
2
)
is ______
Q.
Assertion :Let
F
(
x
)
be an indefinite integral of
cos
3
x
sin
2
x
+
sin
x
.
x
≠
n
π
,
Statement 1 : The function
F
(
x
)
is
1
−
1
on
(
0
,
π
/
2
]
.
Reason: Statement 2 :
log
x
increases from
−
∞
to
0
on
(
0
,
1
]
and
sin
x
increases from
0
to
1
on
(
0
,
π
/
2
]
.
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