The domain of ${sin}^{- 1} [x]$ , where $[x]$ is greatest integer function, given by

[- 1, 1]

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[- 1, 2)

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{- 1, 0, 1}

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None of these

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Solution

The correct option is B $[- 1, 2)$
Domain of ${sin}^{- 1} (x)$ is $[- 1, 1]$
Now $[x]$ is greatest integer function, lesser than or equal to $x .$
Hence
$- 1 \leq [x] \leq 1$
Hence
$x \in [- 1, 2)$

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