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Question

The domain of x+2+1log10(x+1) is

A
(0,)
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B
(1,){0}
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C
(1,0)(1,)
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D
R{2,1}
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Solution

The correct option is B (1,){0}
x+2+1log10(x+1)
For the square root to exist,
x+20
x2,
For the log function, we get
x+1>0x>1,
For 1log10(x+1) to exist,
log10(x+1)0x+11x0
x(1,){0}

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