The domain of the function defined by f(x)=sin−1√x−1 is
A
[1,2]
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B
[0,2]
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C
[0,1]
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D
noneofthese
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Solution
The correct option is A[1,2] For the square root to be defined: x−1≥0⟹x≥1 (1) For inverse sine to be defined, −1≤√x−1≤1 As square is always non-negative: 0≤√x−1≤1 ⟹0≤x−1≤1 ⟹1≤x≤2 (2) Intersection of the two intervals (1) and (2) gives: x∈[1,2]