The domain of the function f defined byfx-1-x-x- is

The given function isf(x)=1√(x |x|) nbsp; It is defined only when x |x| gt;0 ⇒|x| lt;x ∵|x|≥ x,∀ x∈ℝ therefore, it is not possible for any x Hence, t ...

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The domain of the function $f$ defined by $f (x) = \frac{1}{\sqrt{x - | x |}}$ is

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Solution

$The given function is f (x) = \frac{1}{\sqrt{x - | x |}}$

$It is defined only when x - | x | > 0$

$\Rightarrow | x | < x$

$∵ | x | \geq x, \forall x \in R$

therefore, it is not possible for any $x$

Hence, the option (D) is correct.

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The domain of the function f defined byf(x)=1√x−|x| is

The given function isf(x)=1√x−|x| It is defined only when x−|x|>0 ⇒|x|<x ∵|x|≥x,∀x∈R therefore, it is not possible for any x Hence, the option (D) is correct.

The domain of the function $f$ defined by $f (x) = \frac{1}{\sqrt{x - | x |}}$ is

$The given function is f (x) = \frac{1}{\sqrt{x - | x |}}$

$It is defined only when x - | x | > 0$

$\Rightarrow | x | < x$

$∵ | x | \geq x, \forall x \in R$

therefore, it is not possible for any $x$

Hence, the option (D) is correct.