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Question

The domain of the function f(x)=4x2cos1(2x) is

A
[0,2]
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B
[0,2)
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C
[1,2)
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D
[1,2]
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Solution

The correct option is C [1,2)
Given, f(x)=4x2cos1(2x)

For f(x) to be defined 4x20,12x1 and 2x1

2x2 and 12x1

2x2 and 3x1

2x2 and 1x3

Domain of f(x)=[1,2)

697820_654841_ans_b0e736c22e9948b9bb3625c880467b8a.png

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