Question

The domain of the function f (x) = $\frac{1}{\sqrt{x-3}}$ is given by :

• A. $x<3$
• B. $x>3$
• C. $x$ $\ge$ $-3$
• D. $x$ $\le$ $3$

Answer 1

The correct option is B $x>3$

The function will not be defined when the denominator is 0 or when the square root has a negative number.

Hence combination of the conditions

$x\ne 3$ and $x\ge 3$ gives:

$x>3$