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Question

The domain of the function f(x)=log1/2(x12)+log24x24x+5 is

A
[12,)
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B
(12,)
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C
(,)
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D
(12,)
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Solution

The correct option is B (12,)
f(x)=log1/2(x12)+log24x24x+5
log1/2(x12) is defined if x12>0 i.e., x>12,
and log24x24x+5 is defined if
4x24x+5>0
4[(x12)2+1]>0 which is true for all real x.
Domain of f is (12,)

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