CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The domain of the function f(x)=log1/2(x12)+log24x24x+5 is

A
[12,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(12,)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(12,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (12,)
f(x)=log1/2(x12)+log24x24x+5
log1/2(x12) is defined if x12>0 i.e., x>12,
and log24x24x+5 is defined if
4x24x+5>0
4[(x12)2+1]>0 which is true for all real x.
Domain of f is (12,)

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Resonance Experiment
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon