The domain of the function f(x)=log3log1/3(x2+10x+25)+1[x]+5 where [.] denotes the greatest integer function) is
A
(−4,−3)
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B
(−6,−5)
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C
(−6,4)
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D
None of these
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Solution
The correct option is B(−6,−5) For given function to be defined, (i) x2+10x+25>0⇒(x+5)2>0⇒x≠−5=D1 (ii) log1/3(x2+10x+25)>0⇒x2+10x+25<1 ⇒x2+10x+24<0⇒(x+4)(x+6)<0⇒x∈(−6,−4)=D2 and (iii) [x]+5≠0⇒x∉[−5,4)=D3 Hence domain of f is D!∩D2∩D3=(−6,−5)