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Question

The domain of the function f(x)=logx+12|x25x+6| is

A
[32,2)(2,3)(3,)
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B
[32,)
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C
[12,)
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D
None of these
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Solution

The correct option is C [12,)
f(x)=logx+12|x25x+6|

=>(x+12)>1
Which gives =>x>12 (1)

For |x25x+6|:
By putting it to zero the roots will be:
x23x2x+6=0
Gives: (x2)(x3)=0
so the roots are x=2,3
The Domain for |x25x+6| is all real values (2)
From Equation (1) and (2):
x[12,)

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