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Question

The domain of the function f(x)=secx+tanx is

A
R{(2n+1)π2, nZ}
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B
R{nπ, nZ}
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C
R{0}
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D
R
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Solution

The correct option is A R{(2n+1)π2, nZ}
Domain of secx=R{(2n+1)π2, nZ}=D1
Domain of tanx=R{(2n+1)π2, nZ}=D2
Domain of f(x)=D1D2=R{(2n+1)π2, nZ}

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