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Byju's Answer
Standard XII
Mathematics
Real Valued Functions
The domain of...
Question
The domain of the function
f
(
X
)
=
√
3
−
2
x
−
2
1
−
x
+
√
s
i
n
−
1
x
is
A
[-1, 0]
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B
[0, 1]
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C
[
1
2
,
1
]
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D
[1,2]
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Solution
The correct option is
B
[0, 1]
s
i
n
−
1
x
≥
0
⇒
0
≤
x
≤
1
and
2
x
+
2
1
−
x
≤
3
⇒
2
x
+
2.2
−
x
−
3
≤
0
Put
2
x
=
t
, then
t
2
−
3
t
+
2
≤
0
⇒
(
t
−
2
)
(
t
−
1
)
≤
0
⇒
1
≤
t
≤
2
i.e
1
≤
2
x
≤
2
⇒
0
≤
x
≤
1
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7
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