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Question

The domain of the function sin2x is

A
[nππ2,nπ],nZ
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B
[nπ,nπ+π2],nZ
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C
[(2n1)π,2nπ],nZ
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D
[2nπ,(2n+1)π],nZ
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Solution

The correct option is B [nπ,nπ+π2],nZ
For sin2x to be defined,
sin2x0
2x[2nπ,(2n+1)π]
x[nπ,nπ+π2],nZ

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