The domain of the real-valued function fx - x - 3x - 1-x2 - 4 is

The correct option is B R [ 2, 2] f(x)=x 3(x 1)√(x^2 4) x^2 4 ≠ 0 , #160; #160; #160; #160; #160; #160; x 1 #160; #160 ...

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Byju's Answer

Standard XII

Mathematics

Definition of Functions

The domain of...

Question

The domain of the real-valued function $f (x) = \frac{x - 3}{(x - 1) \sqrt{x^{2} - 4}}$ is

(1, 3)

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R - [- 2, 2]

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(- \infty, - 2) \cup (1, \pm \infty)

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R - (1, 2, - 2)

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Solution

The correct option is B $R - [- 2, 2]$
$f (x) = \frac{x - 3}{(x - 1) \sqrt{x^{2} - 4}}$
$x^{2} - 4 \neq 0, x - 1 \neq 0$
$∴ x \neq 1, - 2, 2$
$x^{2} - 4 > 0$
$∴ x = R - [- 2, 2]$
$∴ D o m a i n = R - [- 2, 2]$

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The domain of the real-valued function f(x)=x−3(x−1)√x2−4 is

The correct option is B R−[−2,2]f(x)=x−3(x−1)√x2−4x2−4≠0,x−1≠0∴x≠1,−2,2x2−4>0∴x=R−[−2,2]∴Domain=R−[−2,2]

The domain of the real-valued function $f (x) = \frac{x - 3}{(x - 1) \sqrt{x^{2} - 4}}$ is

The correct option is B $R - [- 2, 2]$
$f (x) = \frac{x - 3}{(x - 1) \sqrt{x^{2} - 4}}$
$x^{2} - 4 \neq 0, x - 1 \neq 0$
$∴ x \neq 1, - 2, 2$
$x^{2} - 4 > 0$
$∴ x = R - [- 2, 2]$
$∴ D o m a i n = R - [- 2, 2]$