wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The driver link AB of a four-bar mechanism is rotated at 5.0 rad/s in counter clockwise direction as shown in the figure below. The angular velocity (rad/s) of the coupler at instant when θ=180 is ____rad/sec

  1. 2.5

Open in App
Solution

The correct option is A 2.5
Given that ω2=5 rad/s

Need to find out ω3 when BAD=180


According to Kennedy's theorem

I24 is at the intersection of link 1 and 3 and I13 at the intersection of links '2' and '4'.

At AI12

BI23,I24

CI34

DI13,I14

From angular velocity-ratio theorem

ω4ω2=I24I12I24I14=2=0.5

ω4=2.5 rad/s(counter clockwise)

V2=(I12,I23)×ω2=(I13,I23)×ω3

l×5=2l×ω3

ω3=2.5 rad/sec

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon