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Question

The driver of a car moving at a speed of 10 m/s applies the brakes after noticing an obstacle. The retardation due to the brakes is 4 m/s2. What is the distance travelled by the car till it stops?

A
12 m
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B
12.5 m
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C
10 m
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D
11 m
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Solution

The correct option is B 12.5 m
We know,
u=10 m/s
a=4 m/s2

Let's say the car stops at t s
At t s, v=0 (because the car stopped)
Using the 1st equation
v=u+at
We get,
0=10+(4)t
4t=10
t=104=2.5 s

To get the distance travelled by the car we can use the 2nd equation of motion
s=ut+12at2
Replacing values of u, a and t in this equation, we get
s=ut+12at2=(10×2.5)12×4×2.52
s=12.5 m

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