the driver of a train running at 97 km/h suddenly observes another train moving on the same track 60m ahead in the same direction the speed of the second train is 48 km/h the second driver instantly applies break how much constant declaration is required to avoid the collision between the two trains

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Solution

Dear Student,
$H e r e f o r a v o i d i n g c o l l i s i o n b o t h s h o u l d a p p l y b r e a k l e t t h e y a p p l y s i m u l a \tan o u s l y r a l a t i v e v e l o c i t y (u) = 97 + 48 = 145 k m / h = \frac{145 \times 5}{18} m / s a n d r e l a t i v e d e c c e l a r a t i o n = \frac{u^{2}}{2 s} = \frac{\frac{145 \times 5}{18} \times \frac{145 \times 5}{18}}{2 \times 60} = 13.7 m / s^{2}$
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Dear Student, Herefor avoiding collision both should apply break let they apply simulatanously ralative velocity (u)= 97+48=145km/h=145×518m/sand relative deccelaration =u22s=145×518×145×5182×60=13.7m/s2 Regards