The driver of a train traveling at 40 ms−1 applies the brakes as the train enters a station. The train slows down at a rate of 2 ms−2. The distance traveled by train before stopping is
Given, the initial speed u=40 ms−1, acceleration a=−2 ms−2 (Retardation as it is negative), final velocity v=0 and distance traveled by train before stopping is s
Using equation of motion,
v2=u2+2as
⇒02=402+2×−2×s
On solving s=400 m