Question

The dynamic load capacity of 6306 bearing is 22 kN. The maximum radial load it can sustain to operate at 600 rev/min, for 2000 hours is

• A. $6.25kN$
• B. $5.29kN$
• C. $4.16kN$
• D. $3.60kN$

Answer 1

The correct option is B $5.29kN$

$L=600\times 60\times 2000=72\times {10}^{6}rev$
$L={\left(\frac{C}{P}\right)}^3\times {10}^{6}rev$
$72\times {10}^6={\left(\frac{22}{P}\right)}^3\times {10}^6$
$P=5.29kN$