The E.A.N. of central metal atom in $[C o (N H_{3})_{6}] C l_{3}$ is $[$ At. No. of Co = 27]

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36

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Solution

The correct option is C $36$
The E.A.N. of central metal atom in $[C o (N H_{3})_{6}] C l_{3}$ is 36.
$E . A . N = 27 - 3 + 12 = 36$
The atomic number of Co is 27.
The oxidation state of Co in the complex is +3.
The number of electrons lost by Co to form Co(III) ion is 3.
6 ammonia ligands donate 6 electron pairs or 12 electrons to Co.

Option C is correct.

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