Question

The $E_{cell}$ for a given cell is $1.2346$ and $1.2340V$ at $300$ K and $310$ K, respectively. Calculate the change in entropy during the cell reaction if the redox change involves three electrons.

• A. $-17.37$ $J{K}^{-1}$
• B. $+17.37$ $J{K}^{-1}$
• C. $173.7$ $J{K}^{-1}$
• D. $5.79$ $J{K}^{-1}$

Answer 1

The correct option is A $-17.37$ $J{K}^{-1}$

$By\Delta S=\frac{\Delta -\Delta G}{T};$
$\Delta H=-nF[E-T{\left(\frac{\partial E}{\partial T}\right)}_p]and\Delta G=-nEF$
$\Delta S=-nF{\left(\frac{\partial E}{\partial T}\right)}_p=3\times 96500\times (-\frac{0.0006}{10})$
$=17.37J$ $K^{-1}$