The e.m.f. of a cell corresponding to the reaction Zn+2H+(aq)→Zn2+(0.1M)+H2(g)(1atm) is 0.26 volt at 25∘C. The pH of the solution at the hydrogen electrode is: (E∘Zn2+/Zn=−0.76 V and E∘H+/H2=0)
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Solution
Ecell=0.26
E∘cell=E∘H+/H2−E∘Zn2+/Zn
E∘cell=0−(−0.76)=0.76V Applying Nernst equation: Ecell=E∘cell−0.05912log[Zn+2][PH2][H+]2 0.26=0.76−0.05912log[0.1][1][H+]2 log0.1[H+]2=2×0.500.0591 or log0.1−log[H+]2=17 or 2pH=17−log0.1=18 pH =182=9