The e.m.f of a cell is 2.0V and the internal resistance is 0.1Ω. It is connected with a resistance of 3.9Ω. Then potential difference across the cell is :-
A
0.20V
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B
1.90V
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C
1.95V
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D
2.00V
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Solution
The correct option is C1.95V Current in the circuit is i=23.9+0.1=0.5A Potential across cell=emf of cell− potential across internal resistance =2−(0.1×0.5)=1.95V