The $e . m . f$ of a lead accumulator cell is 2 volts. Explain.

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Solution

The electromotive force ( $e . m . f$ ) of a cell is defined as the energy supplied by the cell or battery per unit charge ( $q$ ) passing through it.
$E . M . F$ is equal to the terminal potential difference when no current flows.
The $e . m . f$ of a lead accumulator cell is 2 volts, which means when no current flows through the circuit the terminal potential difference is 2V.

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The e.m.f of a lead accumulator cell is 2 volts. Explain.

The $e . m . f$ of a lead accumulator cell is 2 volts. Explain.