The e-m-f- of the cell involving following changes- Zns - Ni2- 1 M - Zn2- 1 M - Nis is 0-5105 V-The standard e-m-f- of the cell is-

The correct option is D 0.5105 V According to Nernst equation, E #160;= #160;E^o 0.0591n× logQ Zn(s) + Ni^2+ (1 M) #160;→ Zn^2+ (1 M) + ...

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Nernst Equation

The e.m.f. of...

Question

The e.m.f. of the cell involving following changes, $Z n (s) + N i^{2 +} (1 M) \to Z n^{2 +} (1 M) + N i (s)$ is $0.5105 V .$
The standard e.m.f. of the cell is:

0.540 V

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0.4810 V

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0.5696 V

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0.5105 V

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Solution

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Similar questions

Z n (s) + N i^{2 +} (0.1 M) \to Z n^{2 +} (1.0 M) + N i (s)

0.5105 V

298 K

E^{o}

{Z n}^{2 +} | Z n

- 0.76

Z n ∣ ∣ {Z n}^{2 +} (1 M) ∣ ∣ ∣ ∣ 2 H^{+} (1 M) ∣ ∣ H_{2} (1 a t m)

Z n | Z n^{2 +} | | N i^{2 +} | N i

Z n^{2 +} | Z n

N i^{2 +} | N i

- 0.76 V

- 0.25 V

Z n {/ Z n}^{2 +} ∥ {N i}^{2 +} / N

E^{o}

{Z n}^{2 +} / Z n = - 0.76 V

E^{o}

{N i}^{2 +} / N i = - 0.25 V

Z n | {Z n}^{2 +} (0.1 M) ∥ {P b}^{2 +} (1 M) | P b

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