The e-m-f of the cell is- Mg - Mg 2-1 M P b 2-1 M - Pb - E Pb - Pb 2-0-0-14 V - E Mg 2 - Mg 0-2-37 V -A- -2-51 VB- -2-23 VC- 2-23 VD- 2-51 V

The correct option is C 2.23 VE^0 = E^0_(Pb^2+/Pb ) E^0_(Mg^2+/Mg ) = E^0_(Pb/Pb^2+ ) E^0_(Mg^2+/Mg ) = 0.14 ( 2.37) = 2.23 V ...

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Definition of Functions

The e.m.f of ...

Question

The e.m.f of the cell is: $M g | M g^{2 +} (1 M) | | P b^{2 +} (1 M) | P b$ $[E_{(P b / P b^{2 +})}^{0} = 0.14 V, E_{(M g^{2 +} / M g)}^{0} = - 2.37 V]$

- 2.51 V

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- 2.23 V

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2.23 V

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2.51 V

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S n (s) | S n^{2 +} (a q ., 1 M) | | P b^{2 +} (a q ., 1 M) | P b (s)

\frac{[S n^{2 +}]}{[P b^{2 +}]}

E_{\frac{S n^{2 +}}{S n}}^{\circ} = - 0.14 V; E_{\frac{P b^{2 +}}{P b}}^{\circ} = - 0.13 V, \frac{2.303 R T}{F} = 0.06 V)

E^{0}

E

S n | {S n}^{2 +} (1 M) ∥ {P b}^{2 +} (10^{- 3} M) | P b, E^{0} ({S n}^{2 +} / S n) = - 0.14 V, E^{0} ({P b}^{2 +} / P b) = - 0.13 V

E_{M} g^{2} + | M g

E_{M} g^{2} + | M g^{Θ}

\frac{0.059}{2} l o g \frac{1}{[M g^{2 +}]}

E_{M g^{2 +} | M g}

l o g [M g^{2 +}]

E_{\frac{M g^{2 +}}{M g}} = E_{\frac{M g^{2 +}}{M g}}^{\circ} - \frac{0.059}{2} l o g (\frac{1}{M g^{2 +}})

E_{\frac{M g^{2 +}}{M g}} v s l o g [M g^{2 +}]

P b + S n^{2 +} \to P b^{2 +} + S n

P b \to P b^{2 +}, E^{o} = 0.13 V

S n^{2 +} + 2 e^{-} \to S n; E^{o} = - 0.14 V

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