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Question

The e.m.f of the cell obtained by combining Zn and Cu electrode of a Daniel cell with N calomel electrode in two different arrangements are 1.083 V and 0.018 V respectively at 25C. If the standard reduction potential of N calomel electrode is 0.28 V the emf (V) of Daniel cell is ______ (write the value to the nearest integer)

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Solution

The potential of Zn electrode =1.0830.28=0.803V
The potential of Cu electrode =0.0180.28=0.262V
The emf (V) of Daniel cell =0.803(0.262)=1.1V

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