The e-m-f- of the following cell containing two hydrogen electrodes isPt - 1-2 H 2 g - H -10-8 M M -0-001 M - 1-2 H 2 g P tA- 0-295 VB- 0-0295 VC- 0-0590 VD- Zero

The correct option is A 0.295VE=E^0 0.059/1 log 10^ 8/10^ 3 E=E^0+0.059 log 10^5 =0+0.059 × 5 = 0.295V ...

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Nersnt Equation

The e.m.f. of...

Question

The e.m.f. of the following cell containing two hydrogen electrodes is
$P t, \frac{1}{2} H_{2} (g) | H^{+} (10^{- 8} M) | | M^{+} (0.001 M) | \frac{1}{2} H_{2} (g) P t$

0.295V

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0.0295V

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0.0590V

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Zero

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