The e/m of three singly ionized atoms A, B and C are x, y, z respectively. If x > y > z and $m_{A}, m_{B}$ , and $m_{C}$ are their atomic weights, the correct relation among the following is _________.

m_{A} > m_{B} > m_{C}

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m_{C} > m_{B} > m_{A}

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m_{A} = m_{B} = m_{C}

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m_{A} > m_{B} = m_{C}

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Solution

The correct option is B $m_{C} > m_{B} > m_{A}$
$\begin{matrix} x = \frac{e}{m_{A}} y = \frac{c}{m_{B}} z = \frac{e}{m_{C}} ∵ x > y > z \frac{e}{m_{n}} > \frac{e}{m_{B}} > \frac{e}{m_{c}} \frac{1}{m_{A}} > \frac{1}{m_{B}} > \frac{1}{m_{C}} ∴ m_{C} > m_{B} > m_{A} \end{matrix}$

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The e/m of three singly ionized atoms A, B and C are x, y, z respectively. If x > y > z and mA,mB, and mC are their atomic weights, the correct relation among the following is _________.

The correct option is B mC>mB>mAx=emAy=cmBz=emC∵x>y>zemn>emB>emc1mA>1mB>1mC∴mC>mB>mA

The e/m of three singly ionized atoms A, B and C are x, y, z respectively. If x > y > z and $m_{A}, m_{B}$ , and $m_{C}$ are their atomic weights, the correct relation among the following is _________.

The correct option is B $m_{C} > m_{B} > m_{A}$
$\begin{matrix} x = \frac{e}{m_{A}} y = \frac{c}{m_{B}} z = \frac{e}{m_{C}} ∵ x > y > z \frac{e}{m_{n}} > \frac{e}{m_{B}} > \frac{e}{m_{c}} \frac{1}{m_{A}} > \frac{1}{m_{B}} > \frac{1}{m_{C}} ∴ m_{C} > m_{B} > m_{A} \end{matrix}$