The Eo for the reaction H2O2- 2H-O2-2e- is -0-68 V-Which nature of H2O2 does the above reaction represent-

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Reductions Involving Aldehydes or Ketones

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Question

The $E^{o}$ for the reaction $H_{2} O_{2} \to 2 H^{+} + O_{2} + 2 e^{-}$ is $- 0.68 V$ .
Which nature of $H_{2} O_{2}$ does the above reaction represent?

Bleaching

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Acidic

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Reducing

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Oxidising

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H_{2} O_{2} \to 2 H^{+} + O_{2} + 2 ¯ e; E^{\circ} = - 0.68 V

H_{2} O_{2}

H_{2} O_{2}

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

H_{2} O_{2} + 2 O H^{-} 2 e^{-} \to O_{2} + 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2}

H_{2} O_{2} + 2 H^{+} + 2 e \to 2 H_{2} O

H_{2} O_{2} - 2 e \to O_{2} + 2 H^{+}

H_{2} O_{2} + 2 e \to 2 (O H^{-})

H_{2} O_{2} + 2 O H^{-} - 2 e \to O_{2} + 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

H_{2} O_{2} + 2 O H^{-} - 2 e^{-} \to O_{2} + 2 H_{2} O

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