The E $^{o}$ in the given diagram is:

0.523

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0.613

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0.715

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0.825

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Solution

The correct option is B 0.613
$C i O_{3} + 2 H_{2} O + 4 e \to C I O^{-} + 4 O H^{-}; Δ G_{1}^{o}$
$C I O^{-} + H_{2} O + e \to \frac{1}{2} C l_{2} + 2 O H^{-}; Δ G_{2}^{o}$
$\frac{1}{2} C l_{2} + e \to C l^{-}$ $; Δ G_{3}^{o}$
---------------------------------------------------------------
$C l O_{3}^{-} + 3 H_{2} O + 6 e \to C l^{-} + 6 O H^{-}$ $; Δ G_{3}^{o}$
---------------------------------------------------------------
$∴ Δ G^{o} = Δ G_{1}^{o} + Δ G_{2}^{o} + Δ G_{3}^{o}$
$- 6 F E^{o} = - 4 F \times 0.54 - 1 F \times 0.45 - 1 F \times 1.07$
$∴ E^{o} = + \frac{3.68}{6} = + 0.613 V$

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E^{0}

F e O_{4}^{2 -} E^{o} = + 2.20 V - ------ \to F e^{3 +} E^{o} = 0.77 V - ----- \to F e^{2 +} F e^{2 +} E^{o} = 0.445 V - ------ \to F e^{0}

E_{F e O_{4}^{2 -} / F e^{2 +}}^{o}

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