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Standard XII

Chemistry

Lanthanides Electronic Configuration

The EoM3+/ ...

Question

The $E_{M^{3 +} / M^{2 +}}^{o}$ values for $C r$ , $M n$ , $F e$ and $C o$ are $- 0.41$ , $+ 1.57$ , + $0.77$ and + $1.97$ respectively. For which one of following metal the change in oxidation state from +2 to +3 is easiest?

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Solution

The correct option is A Cr
As we know,

$E_{O P}^{o} = - E_{R P}^{o}$ .

So, $E_{O P}^{o}$ for $C r^{2 +} / C r^{3 +}$ is maximum +0.41 V.

So, $C r^{2 +}$ will be easily oxidised to $C r^{3 +}$ .

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Similar questions

Q. The

_{M^{3 +} / M^{2 +}}^{o}

values for Cr, Mn, Fe and Co are

- 0.41, + 1.57, + 0.77

and

+ 1.97

V respectively. For which one of these metals the change in oxidation state from

+ 2

+ 3

is easiest?

Q. The

E_{M^{3 +} / M^{2 +}}^{\circ}

values of

C r, M n, F e

and

C o

are

- 0.41, + 1.57, + 0.77

and

+ 1.97 V

, respectively. For which one of these metals the change in oxidation state from

+ 2

+ 3

is easiest?

The $E {^{0}}_{M^{3 +} / M^{2 +}}$ values for Cr, Mn, Fe and Co are -0.41, + 1.57, + 0.77 and + 1.97V respectively.For which one of these metals the change oxidation state from +2 and +3 is easily?

Q. Account for the following:
(i) Transition metals show variable oxidation states.
(ii)

Z n, C d

and

H g

are soft metals.
(iii)

E^{\circ}

value of the

M n^{3 +} / M n^{2 +}

couple is highly positive

(+ 1.57 V)

as compared to

C r^{3 +} / C r^{2 +}

Q. (a) Account for the following:
(i) Transition metals show variable oxidation states.
(ii) Zn, Cd and Hg are soft metals.
(iii)

E^{o}

value for the

M n^{3 +} / M n^{2 +}

couple is highly positive (+ 1.57 V) as compared to

C r^{3 +} / C r^{2 +}

.
(b) Write one similarity and one difference between the chemistry of lanthanoid and actinoid elements.

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The EoM3+/M2+ values for Cr, Mn, Fe and Co are −0.41, +1.57, +0.77 and +1.97 respectively. For which one of following metal the change in oxidation state from +2 to +3 is easiest?

The correct option is A CrAs we know,EoOP=−EoRP.So, EoOP for Cr2+/Cr3+ is maximum +0.41 V.So, Cr2+ will be easily oxidised to Cr3+.

The $E_{M^{3 +} / M^{2 +}}^{o}$ values for $C r$ , $M n$ , $F e$ and $C o$ are $- 0.41$ , $+ 1.57$ , + $0.77$ and + $1.97$ respectively. For which one of following metal the change in oxidation state from +2 to +3 is easiest?

The correct option is A Cr
As we know,

$E_{O P}^{o} = - E_{R P}^{o}$ .

So, $E_{O P}^{o}$ for $C r^{2 +} / C r^{3 +}$ is maximum +0.41 V.

So, $C r^{2 +}$ will be easily oxidised to $C r^{3 +}$ .