Question

The $EAN$ value of ${\left[Ti{(\sigma -C_5{H}_5)}_2{(\pi -C_5{H}_5)}_2\right]}^0$ is:

• A. $32$
• B. $33$
• C. $34$
• D. $35$

Answer 1

Answer: (A)

$32$

$\left[Ti\right(L_5{H}_5{)}_2]$

Electron$=22\left(Ti\right)+(2\times 5)=32$

$C_2{H}_5=$contribute $5e^{-}$ each