Question

The earth $(mass=6\times {10}^{24}kg)$ revolves around the sun with an angular velocity of $2\times {10}^{-7}$ rad/s in a circular orbit of radius $1.5\times {10}^8$ . The force exerted by the sun on the earth, in newtons, is:

• A. $36\times {10}^{21}$
• B. $27\times {10}^{39}$
• C. $0$
• D. $18\times {10}^{25}$

Answer 1

Answer: (A)

$36\times {10}^{21}$

Given,

$m=6\times {10}^{24}kg$

$\omega =2\times {10}^{-7}rad/s$

$R=1.5\times {10}^{8}km$

Force, $F=m{\omega }^{2}R$

$F=6\times {10}^{24}\times 2\times {10}^{-7}\times 2\times {10}^{-7}\times 1.5\times {10}^8\times {10}^3$

$F=36\times {10}^{21}N$

The correct option is A.