Question

The earth ($mass=6\times {10}^{24}$ kg)revolves around the sun with an angular velocity of $2\times {10}^{-7}$ rad/s in a circular orbit of radius $1.5\times {10}^8$ km. The force exerted by the sun on the earth, in newtons, is

• A. $36\times {10}^{21}$
• B. $27\times {10}^{39}$
• C. Zero
• D. $18\times {10}^{25}$

Answer 1

The correct option is A $36\times {10}^{21}$

Given:

$m=6\times {10}^{24}kg\omega =2\times {10}^{-7}rad/sR=1.5\times {10}^{8}km\therefore F=(6\times {10}^{24}kg)(2\times {10}^{-7}rad/s{)}^2\times 1.5\times {10}^8\times {10}^{3}m=36\times {10}^{21}N$