Question

The earth (mass = 6 x ${10}^{24}$ kg ) revolves around the sun with an angular velocity of 2 x ${10}^{-7}$ rad/s in a circular orbit of radius 1.5 x ${10}^8$ km . The force exerted by the sun on the earth, in newtons, is:

• A. 36 x ${10}^{21}$
• B. 27 x ${10}^{39}$
• C. 0
• D. 18 x ${10}^{25}$

Answer 1

The correct option is A 36 x ${10}^{21}$

Force exerted by sun of earth $=MW2R$

given $M=6\times {10}^{24}kg$

$W=2\times {10}^{-7}$ rod/s

$R=1.5\times {10}^{8}km$

$F=(6\times {10}^{24})(2\times {10}^{-7})2(1.5\times {10}^8\times {10}^3)$

$=36\times {10}^{21}N$