The earth's magnetic field at some place on magnetic equator of the earth is 0.5×10−4T. Consider the radius of the earth at that place as 6400km. Then, magnetic dipole moment of the earth is ___________ Am2. (μ0=4π×10−7TmA−1)
A
1.31×1023
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B
1.05×1023
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C
1.15×1023
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D
1.62×1023
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Solution
The correct option is D1.62×1023 Given, Re=6400km=6.4×10+6m Be=0.5×10−4T μ0=4π×10−7TmA−1 M=? The magnetic field at the equator B=μ04π⋅iRe and M=iA M=4πRe⋅Bμ0×πR2e =4π×64×105×5×10−5×3.14×4096×10104π×10−7 =130×107×3.14×4096×1010 =1673508.57×1017 =1.67×1023Am2