CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The earth's magnetic field at the equator is approximately 0.4$$G$$. Estimate the Earth's dipole moment.


A
1.05×1023Am2
loader
B
1.05×1023Am2
loader
C
5.01×1023Am2
loader
D
5.01×1023Am2
loader

Solution

The correct option is A $$1.05 \times 10 ^ { 23 } \mathrm { Am } ^ { 2 }$$
$$\begin{array}{l} B=\dfrac { { { \mu _{ o } }M } }{ { 4\pi { d^{ 3 } } } } = \\ \dfrac { { { \mu _{ 0 } } } }{ { 4\pi  } } ={ 10^{ -7 } }w6{ A^{ -1 } }{ m^{ -1 } }\, \, M=dipole\, \, moment \\ d=6400\, \, km=6.4\times { 10^{ 6 } }\, \, m \\ M=\dfrac { { B{ d^{ 3 } } } }{ { { { 10 }^{ -7 } } } } =\dfrac { { 4\times { { 10 }^{ -4 } }\times { { \left( { 6.4\times { { 10 }^{ 6 } } } \right)  }^{ 3 } } } }{ { { { 10 }^{ -7 } } } }  \\ =1.05\times { 10^{ 23 } }A{ m^{ 2 } } \end{array}$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image