Question

The ease of dehydrohalogenation for different halogens is in the order:

• A. iodide > bromide > chloride
• B. bromide > iodide > chloride
• C. chloride > bromide > iodide
• D. iodide > chloride > bromide

Answer 1

The correct option is A iodide > bromide > chloride

$I^{-}$ is most stable due to large size and weakest bond due to its longest bond length.

For the given halogen, this order will be:

$R-I>R-Br>R-Cl$

So, option A is correct.