The ease of esterification of following alcohols with HCOOH will be highest for
$C H_{3} C H_{2} O H 1$ $(C H_{3})_{2} C H O H 2$ $(C H_{3})_{3} C O H 3$

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Solution

Larger is the size of alcohol, more difficult it will be for an alcohol to attack the carbonyl group of protonated acid and there is too much steric crowding in a tetrahedral complex.

Hence primary alcohol reacts faster.

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Similar questions

{C H}_{3} {C H}_{2} O H (I), {({C H}_{3})}_{2} C H O H

{({C H}_{3})}_{3} C O H (I I I)

H C O O H

C H_{3} C H_{2} O H + H C l a n h . Z n C l_{2} - ----- \to

C H_{3} C H_{2} O H + H C l \to

(C H_{3})_{3} C O H + H C l \to

(C H_{3})_{2} C H O H + H C l a n h . Z n C l_{2} - ----- \to

C H_{3} C H_{2} O H + H C l a n h . Z n C l_{2} - ----- \to

C H_{3} C H_{2} O H + H C l \to

(C H_{3})_{3} C O H + H C l \to

(C H_{3})_{2} C H O H + H C l a n h . Z n C l_{2} - ----- \to

C H_{3} C O O H + C H_{3} C H_{2} O H H_{2} S O_{4} - --- \to

H_{2} O

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