Question

The eccentric angle of one end of a diameter of $x^2+3y^2=3$ is $\frac{\pi }{6}$, then the eccentric angle of the other end will be:

• A. $\frac{5\pi }{6}$
• B. $-\frac{5\pi }{6}$
• C. $-\frac{2\pi }{3}$
• D. $\frac{2\pi }{3}$

Answer 1

The correct option is B $-\frac{5\pi }{6}$

We know, $\frac{\Pi }{6}+\theta =\pi$

$\Rightarrow \theta =\frac{5\pi }{6}$ in anticlockwise direction

So, eccentric angle is $-\frac{5\pi }{6}$