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Question

The eccentric angle of the point of contact of the line xa+yb=2 with the ellipse x2a2+y2b2=1, is:

A
0
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B
π3
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C
π4
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D
π2
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Solution

The correct option is C π4
At any point θ equation of tangent to the ellipse x2a2+y2b2=1 is given by,
xcosθa+ysinθb=1 comparing it with the given line
we get, cosθ=sinθ=12θ=π4

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