wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The eccentricity of a hyperbola whose transverse axis is along x axis and passes through the point (6,4) is 53. The equation of tangent to this hyperbola at (6,4) is

A
x+y2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
xy2=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
xy+2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x+y+2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B xy2=0
e=53e2=1+b2a2
2a2=3b2(i)
Assuming the equation of the hyperbola be,
x2a2y2b2=1
Putting the point (6,4) in the equation of hyperbola,
36a216b2=1
Using equation (i),
a2=12b2=8

x212y28=1x6yy4=0
Putting the point (6,4)
dydx=1
Equation of tangent is,
(y4)=1(x6)
xy2=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
T1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon