Question

The eccentricity of the ellipse $\frac{x^2}{16}+\frac{y^2}{25}=1$ is

• A. $\frac{4}{5}$
• B. $\frac{3}{5}$
• C. $\frac{2}{5}$
• D. $\frac{1}{5}$

Answer 1

The correct option is B $\frac{3}{5}$

Given equation of the ellipse is,
$\frac{x^2}{16}+\frac{y^2}{25}=1$
So $a^2=16$ and $b^2=25$
Eccentricity
$e=\sqrt{1-\frac{a^2}{b^2}}=\sqrt{1-\frac{16}{25}}=\frac{3}{5}$