The eccentricity of the ellipse, if the distance between the foci is equal to the length of the latus-rectum, is
A
√5−12
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B
√5+12
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C
√5−14
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D
none of these
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Solution
The correct option is A√5−12 According to the question, the distance between the foci is equal to the length of the latus rectum 2b2a=2ae ⇒b2=a2e Now, e=√1−b2a2 ⇒e=√1−a2ca2 ⇒e=√1−e On squaring both sides, we get: e2+e−1=0 ⇒e=−1±√1+42 ⇒e=√5−12(∵ecannotbenegative)