The eccentricity of the ellipse, if the minor axis is equal to the distance between the foci, is
A
√32
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B
2√3
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C
1√2
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D
√23
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Solution
The correct option is C1√2
According to the question, the minor axis is equal to the distance between the foci i.e. 2b= 2ae ⇒e=ba ...(1) Now, e=√1−b2a2 ⇒e=√1−e2 [From (1)] On squaring both sides, we get: e2=1−e2 ⇒2e2=1 ⇒e2=12 ⇒e=1√2