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Question

The eccentricity of the ellipse x2a2+y2b2=1, a<b, is given by ___________.

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Solution

For x2a2+y2b2=1 ; a<b
eccentricity, e=1-a2b2
i.e e2=1-a2b2i.e b2e2=b2-a2i.e a2=b21-e2

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