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Standard XII

Chemistry

Relation Between r and a

The edge leng...

Question

The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm.

$N_{A} = 6 \times 10^{2} 3$

457.8 pm

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216.5 pm

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789.5 pm

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257.8 pm

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Solution

The correct option is B
216.5 pm

Watch the video that follows.

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Similar questions

The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm.

$N_{A} = 6 \times 10^{2} 3$

Q. The edge length of unit cell of a metal having molecular weight 75 g/mol is 5

˚ A

which crystallises in cubic lattice. If the density is 2 g/cc then find the radius of a metal atom. (

N_{A} = 6 \times 10^{23}

). Give the answer in pm.

Q. The edge length of unit cell of a metal having molecular weight

75

g/mol is

5 ˚ A

which crystallizes in cubic lattice. If the density is

2 g / c c

, then find the radius (in pm) of metal atom

(N_{A} = 6 \times 10^{23})

. Give answer in

p m

Q. The edge length of a unit cell of a metal that has a molecular weight 75 g/mol is

5 \circ A

. It crystallizes in a cubic lattice. If its density is 2 g/cc, then find the radius of metal atom in pm:

(N_{A} = 6 \times 10^{23}, \sqrt{2} = 1.41, \sqrt{3} = 1.73)

Q. The edge length of a unit cell of a metal having molecular weight

75

g/mol is

5 ˚ A

which crystallizes in a cubic lattice. If the density is

2

g cm

^{- 3}

, then find the radius (in pm) of the metal atom.

[Use

N_{A} = 6 \times 10^{23}

]

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The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm. NA=6×1023

The correct option is B 216.5 pm Watch the video that follows.

The edge length of a unit cell of a metal whose molecular weight is 75 g/mol is 5 angstrom. This crystallises in a cubic lattice. If the density is 2 g/cc, find the radius of the metal atom. Give the answer in pm.

$N_{A} = 6 \times 10^{2} 3$

The correct option is B
216.5 pm

Watch the video that follows.